Hidup Sehat

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Thursday, May 10, 2012

Pembahasan Problem Set 3 - Dasar (no.6-10)

no.6

-5≤y≤-1

no.7
a.b.c.d.e=128
a.ar.ar2.ar3.ar4 = 128
a5.r(1+2+3+4) = 27
a5.r10 = 27
ar2 = 27/5
U3 = 27/5

no.8


no.9
x2+ax-a2=0
44)=(α22)2-2(αβ)2
=[(α+β)2-2αβ]2-2(αβ)2
=[a2+2a2 ]2-2(-a2)2
=9a4-2a4
=7a4


no.10

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