no. 6
no. 7
x2 – x + 2 = 0
p+q = 1 dan p.q = 2
Persamaan kuadrat baru dengan akar-akar: (2p – 3) dan (2q – 3)
| (2p-3) + (2q-3) | = | 2(p+q)-6 |
| = | 2 – 6 = – 4 | |
| (2p – 3)(2q – 3) | = | 4pq – 6(p+q) +9 |
| = | 4(2) – 6(1) + 9 = 11 |
x2 + 4x + 11 = 0
no. 8
y = ax2 + 2x + a2 + 2a
| * | Memotong di (0,3) | |
| 3 = a2 + 2a | ||
| a2 + 2a – 3 = 0 | ||
| (a – 1)(a+3)=0 | ||
| a = 1 atau a = – 3 | ||
| * | Untuk a = 1 | |
| y = x2 + 2x + 3 | ||
| | ||
| | ||
| Minimum (-1,2) |
no. 9
sehingga
no. 10
Banyak kemungkinan = 3.3!=3.3.2.1=18
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