Pembahasan Problem Set 1 - Dasar (no1-5)

no. 1


no. 2
Ralat Soal

no. 3

cos2 (30◦) + cos2 (40◦) + cos2 (50◦) + cos2 (60◦)
= cos2 (30◦) + cos2 (40◦) + sin2 (40◦) + sin2 (30◦)
= 1 + 1 = 2

no. 4

g: (a + 2) + y(a – 2 )=0	→
h: x(-1-3a)+y(5+3a)=5	→

Karena garis g dan h saling tegak lurus, maka m_g. m_h= – 1

	=	– 1
– (a+2)(1+3a)	=	–( a–2)(3a+5)
3a2 + 7a + 2	=	3a2 – a – 10
8a	=	– 12
a	=	– 1,5

no. 5

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